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5 Different colored (black, red, blue, green, and yellow) cards are placed in a row so that the black card is never at either end, how many different arrangements are possible? I don't get why the correct answer is 72.
Please show steps thank you!
Hello Fabxx,
I believe there are other ways to do it, but i did like this...
First calculate total number of arrangements possible : 5!=120
Then calculate the number of arrangements for black to be first: 1*4!=24
And now the number of arrangements for black to be last : 4!*1=24
So Ur answer would be 120-(24+24)= 72