Looking in the z-table, I see the corresponding area are:
For z=2.20, .0.9861
For z=0.85, 0.8023
0.9861-0.8023=.1838
The area under a normal curve between the scores for z=2.20 and z=0.85 is ___.
2.20=0.4861
0.85=0.3023
so, 0.4861+0.3023=0.7884. 0.7884 is my answer, thanks for checking my answer, list of possible anwer are -
1. 0.3023
2. 0.7884
3. 0.1838
4. 0.4861