She checked 120 times, so the relative frequencies (which are our estimateOriginally Posted by kwtolley
of the probabilities) are 20/120, 65/120, .. and so on.
RonL
A secretary periodically checks to see how many of the three lines into the office are busy. Her findings for one week were the following.
No. lines busy Frequency
0 20
1 65
2 25
3 10
Let the random variable X be the number of lines busy. Find the probability distribution of X.
My answer is.
X P(X)
0 0.20
1 0.65
2 0.25
3 0.10
Thanks for checking my answer.