Probability of selecting the first urn.

Ok here it goes,

One urn contains 3 red and 7 white marbles. A second urn contains 2 red and 8 white marbles. One urn is selected and a ball drawn. The probability of selecting the first urn is 0.4 and the probability of selecting the second is 0.6. If a white ball is drawn, find the probability it came from the second urn.

3 red 7 white, urn 1= 10

2 red 8 white, urn 2= 10

P(urn_1)=0.4, P(urn_2)=0.6 0.4*0.6=24

looks like to me urn 2 has a better chance than 1 becaue of th 60%, both have 10 marbles but urn 2 has one more white one than urn 1. List of possible answers are -

1. 0.800

2. 0.632

3. 0.560

4. 0.480 From here I'm stuck in the mud. Need help with the rest of it. thanks for looking over my problem.