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Math Help - binomial distribution

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    binomial distribution

    If 20% of the Aussie population are carriers of the gene for colour blindness, what is the probability that from a group of 7 people chosen at random, at least 3 will be carriers of the gene for colour blindnes??

    Show working please =]
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    Quote Originally Posted by bubbles73 View Post
    If 20% of the Aussie population are carriers of the gene for colour blindness, what is the probability that from a group of 7 people chosen at random, at least 3 will be carriers of the gene for colour blindnes??

    Show working please =]
    \Pr(X \geq 3) = 1 - \left( \Pr(X = 0) + \Pr(X = 1) + \Pr(X = 2) \right).

    What have you tried? Where are you stuck?
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