# combination

• Aug 30th 2008, 05:51 AM
minmin
combination
in the game of poker, what is probability that a five-card hand will contain(a) a straight(five cards in unbroken numerical sequence)
(b) four of a kind
(c) a full house(three cards of one value and two cards of another value)

thanks you so much. I could not figure out.
• Aug 30th 2008, 07:27 AM
Tangera
Hm...I shall attempt this question...not sure if my answer is right though! >.<

(a) Sorry I don't understand what exactly is a straight cos I don't play poker...is J,Q,K,A,2 still considered a straight? If not, then my working is definitely incorrect. And the suits don't matter right?

$Probability = 1 \times \displaystyle{\frac{4}{51}} \times \displaystyle{\frac{4}{50}} \times \displaystyle{\frac{4}{49}}$

(b) $Probability = 1 \times \displaystyle{\frac{12}{51}} \times \displaystyle{\frac{11}{50}} \times \displaystyle{\frac{10}{49}}$
• Aug 30th 2008, 02:33 PM
awkward
Quote:

Originally Posted by minmin
in the game of poker, what is probability that a five-card hand will contain(a) a straight(five cards in unbroken numerical sequence)
(b) four of a kind
(c) a full house(three cards of one value and two cards of another value)

thanks you so much. I could not figure out.

See the following page:

Poker probability - Wikipedia, the free encyclopedia
• Aug 31st 2008, 10:48 AM
minmin
THANKS SO MUCH FOR YOUR INFORMATION, IT MEANS SOMETHING TO ME!