Thread: Probability

In a box there are 22 cubes, 12 red and 10 blue.
7 cubes are chosen at random.
Find the probability for the following events:

a. Among the seven cubes there are 4 blue cubes and 3 red cubes

There are others, but I've tried to do them, and for a I get something like..
0.00780 or something like that.
Which I think might be wrong..
So if anyone could just show me what to do, I think I can do the rest myself, thanks

Hi Fnus,

The probability of getting one blue cube is . Due to the fact that the cubes aren't being replaced the probability of getting another blue cube is and so on and so fourth.

This gives an answer of

Hmm, I think that was what I did..

And I'd multiply them, right?

Maybe I just pressed something wrong.
I'll try again, thanks.

Here is the correct answer:

In case people want a name : Hypergeometric distribution - Wikipedia, the free encyclopedia

Originally Posted by Moo

In case people want a name : Hypergeometric distribution - Wikipedia, the free encyclopedia

I thought it was that...

Oohh...I'm gonna have to deal with that guy and all these other weird distributions this fall in my hardcore stats class...once I survive probability

--Chris

Originally Posted by Plato

Here is the correct answer:

I need to sleep! Thank you for correcting Plato.

Originally Posted by Chris L T521

I thought it was that...

Oohh...I'm gonna have to deal with that guy and all these other weird distributions this fall in my hardcore stats class...once I survive probability

--Chris

Good luck. I'm sure you will enjoy