# Thread: Finding P(Z1|X1Y1) Conditinal Probability..Plz Help..

1. ## Finding P(Z1|X1Y1) Conditinal Probability..Plz Help..

Suppose

X1 Y1 Z1
0 ..0 ..0 (5 times Z1 is 0 for X1=0 and Y1=0)
0.. 0.. 0
0.. 0 ..0
0.. 0 ..0
0 ..0 ..0
0 ..1.. 0
0 ..1 ..0
0 ..1.. 0
0 ..1.. 0
0 ..1 ..0
0 ..1 ..0
0.. 1.. 0
0 ..1.. 1
0 ..1.. 1
0 ..1.. 1
0 ..1 ..1
0 ..1.. 1
0.. 1.. 1
0 ..1.. 1
0 ..1.. 1
.
.
.

Which is..
(Same table which is above..)

X1 Y1.......Z1 (Count of Zeros) (Count of Ones)
0...0 .........................5............2
0...1 .........................7............8
1...0 .........................0............10
1...1 .........................5............1

I have put Dots since Blanks were disappearing once posted hence what is under which column was difficult to understand..dots dont mean anything..

Find P(Z1|X1Y1)?

2. Originally Posted by sanat
Suppose

X1 Y1 Z1
0 ..0 ..0 (5 times Z1 is 0 for X1=0 and Y1=0)
0.. 0.. 0
0.. 0 ..0
0.. 0 ..0
0 ..0 ..0
0 ..1.. 0
0 ..1 ..0
0 ..1.. 0
0 ..1.. 0
0 ..1 ..0
0 ..1 ..0
0.. 1.. 0
0 ..1.. 1
0 ..1.. 1
0 ..1.. 1
0 ..1 ..1
0 ..1.. 1
0.. 1.. 1
0 ..1.. 1
0 ..1.. 1
.
.
.

Which is..
(Same table which is above..)

X1 Y1.......Z1 (Count of Zeros) (Count of Ones)
0...0 .........................5............2
0...1 .........................7............8
1...0 .........................0............10
1...1 .........................5............1

I have put Dots since Blanks were disappearing once posted hence what is under which column was difficult to understand..dots dont mean anything..

Find P(Z1|X1Y1)?
This makes no more sense to me than the first time you posted it.

3. ## Please let me know which part does not make sense..

Also how to find conditional probability with 2 given events..P(Z1|X1,Y1)?
just let me know the formula..thanx..