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Math Help - Organized Counting Problem Help

  1. #1
    Junior Member Morphayne's Avatar
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    Exclamation Organized Counting Problem Help

    Problem:
    A Canadian postal code uses six characters. The first, third, and fifth are letters, while the second, forth, and sixth are digits. A U.S.A. zip code contains five characters, all digits.

    How many codes are possible for each country?

    Comments:


    I'm stuck on this problem...actually I don't understand the 'Permutations and Organized Counting' unit at all... Anyway, can someone please help me with this question?
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  2. #2
    Member
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    Quote Originally Posted by Morphayne View Post
    Problem:
    A Canadian postal code uses six characters. The first, third, and fifth are letters, while the second, forth, and sixth are digits. A U.S.A. zip code contains five characters, all digits.

    How many codes are possible for each country?

    Comments:


    I'm stuck on this problem...actually I don't understand the 'Permutations and Organized Counting' unit at all... Anyway, can someone please help me with this question?
    In general, when dealing with this unit, ask your self 2 questions. Does order matter, and do you pick with replacement or not (i.e. do the possibilities change as you pick from the "pile")?

    Order matters and you do pick with replacement.

    So Canada:
    First spot, how many options?
    26
    Given that, how many options for the second spot?
    10
    Given, that, etc?

    So you get:
    26*10*26*10*26*10 = 26^3*1000 = ....


    Give the US one a try.
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