Let X be the random variable number of aces selected.
Then X ~ Hypergeometric(N = 52, n = 13, m = 4). See Hypergeometric distribution - Wikipedia, the free encyclopedia
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Suppose that 13 cards are selected at random from a regular deck of 52 playing cards. If it is known that at least one ace gas been selected, what is the probability that at least two aces have been selected?
And if it is known that an ace of hearts has been selected, what is the probability that at least two aces have been selected?
Let X be the random variable number of aces selected.
Then X ~ Hypergeometric(N = 52, n = 13, m = 4). See Hypergeometric distribution - Wikipedia, the free encyclopedia
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originally bytanichkap.
you are dealt 13 cars from a 52 card deck;
question is pr of getting 2 or more aces knowing that the hand contains 1 or more aces.
The pr of 2 or more is fixed. The info does not help.If the cards are turned over one by one and an ace shows up between the first and the 12th new prs can be calculated based on where an ace appears.
BJ