If all the letters were different we can choose the letters in sequence, so theOriginally Posted byThe_Hot_Chick

first letter can be chosen in 9 ways, the second in 8 ways, the third in 7, ..

So there would be permutations which we write as for short which is read as nine factorial.

Now we have four "e"s and two "n"s. So for each of the permutations in we in fact have repeats with just the "e"s switched around, and with the "n"s switched around, so the total number of distinct permutations is .

RonL