Is it a coincidence that:
The odds of picking an ace and then a heart WITHOUT REPLACEMENT is the same as picking the ace of hearts?
P(A,heart) = 1/52
P(1,heart)=P(Aheart,heart)+P(A notheart, heart)
= 1/52*12/51 + 3/52*13/51
= (12+39)/(52*51) = 1/52
Is this a coincidence or not, if so, prove it, if not, provide a counterargument.