For the first number, there are 10 possible choices.

For the second number, there are 9 possible remaining choices.

For the third number, there are 8 possible remaining choices.

Therefore, for selecting three numbers,

. . there are: 10 \times 9 \times 8 \:=\:720 possible "combinations".

this is the email i got, but is 720 the answer for all of the "combinations", or just the ones begining with 1??

I AM CONFUSED