- The mean lifetime of a particular type of electric light bulb is 1400 hours, with a standard deviation of 300 hours.

What is the probability that this sample will yield a mean of less than 1390 hours?

Results 1 to 8 of 8

- May 31st 2008, 05:20 PM #1

- Joined
- May 2008
- Posts
- 31

- May 31st 2008, 06:08 PM #2

- Joined
- May 2008
- Posts
- 31

- June 1st 2008, 12:08 AM #3
1. z = -0.033, NOT 0.033.

2. You require Pr(Z < -0.033), NOT Pr(Z > 0.033) and not, for that matter, Pr(Z > -0.033).

3. Although I can figure out most of what you're saying in answer to your own question, if you wrote that way on a homework or test paper in a course of mine, you'd get points deducted from your grade. What you mean (I think) is:

"z = 1390-1400/300 = .033. Then from the z table, Pr(z < 0.033) =.5120"

(I have no idea where "p z >.033=.5120" has come from")

Sure, it takes a few more words to say that, but*words matter.*To communicate mathematics, you have to say exactly what you mean - no more, no less.

- June 1st 2008, 03:56 AM #4

- Joined
- May 2008
- Posts
- 31

- The mean lifetime of a particular type of electric light bulb is 1400 hours, with a standard deviation of 300 hours.

so 1390-1400/300 = -0.033 = 51.20% probability that the sample would yield 1390 hours

which would = p(z < 0.033)=.5120

so if it a negative value then i have to look at negative values on the z table. which then would mean .4840

p(z < 0.033)=.4840

- June 1st 2008, 04:14 AM #5

- June 1st 2008, 06:32 AM #6

- Joined
- May 2008
- Posts
- 31

- June 1st 2008, 01:09 PM #7

- June 1st 2008, 03:03 PM #8

- Joined
- May 2008
- Posts
- 31