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Math Help - probabiity

  1. #1
    key
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    probabiity

    Hi Can someone please help me with the problem below.

    When Bill bowls, he can get a strick 60% of the time. How many times more likely is it for Bill to bowl at least three strikes out of four tries as it is for him to bowl zero strikes out of four tries. Round to nearest whole number.

    I gpt 47 times more likely. Is that correct.

    Thanks
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by key View Post
    Hi Can someone please help me with the problem below.

    When Bill bowls, he can get a strick 60% of the time. How many times more likely is it for Bill to bowl at least three strikes out of four tries as it is for him to bowl zero strikes out of four tries. Round to nearest whole number.

    I gpt 47 times more likely. Is that correct.

    Thanks
    He has a probability of 0,6 to bowl a strike.

    The chances that he gets a strike AT LEAST 3 out of 4 times he bowls:

     <br />
{4 \choose 3} \left( \frac{3}{5} \right)^{3} \left( \frac{2}{5} \right)^{1} <br />
+ {4 \choose 4} \left( \frac{3}{5} \right)^{4} \left( \frac{2}{5} \right)^{0} = \frac{216 + 81}{625} = 0,4752<br />

    The chances that he does not score a strike at all:

     <br />
{4 \choose 0} \left( \frac{3}{5} \right)^{0} \left( \frac{2}{5} \right)^{4} = \frac{16}{625} = 0,0256<br />

    I get 18,56 times more likely.
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