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Math Help - Combination problem

  1. #1
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    Combination problem

    Eight cards are selected with replacement from a pack of 52 playing cards, with 12 pictures, 20 odd cards and 20 even cards.

    - How many different sequences of 8 are available?

    Thanks x
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  2. #2
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    Hello, AshleyT!

    Could you supply the exact wording of the problem?

    And the entire problem?
    We don't need the breakdown of the types of cards.
    . . So I suspect there are more parts to the question.


    Eight cards are selected with replacement from a pack of 52 playing cards.
    How many different sequences of 8 are available?

    Since there are 52 different (identifiable) cards,

    . . there are: . 52^8 \:\approx\:5.346 \times 10^{13} possible sequences.

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  3. #3
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    Quote Originally Posted by Soroban View Post
    Hello, AshleyT!

    Could you supply the exact wording of the problem?

    And the entire problem?
    We don't need the breakdown of the types of cards.
    . . So I suspect there are more parts to the question.



    Since there are 52 different (identifiable) cards,

    . . there are: . 52^8 \:\approx\:5.346 \times 10^{13} possible sequences.

    Hey, thanks very much for the reply .

    There are second parts of the question but that was the first part, and the part i was stuck with. I'm going to attempt the other parts now.

    Basically the chapter is based around factorials and holds no examples of using powers, so i didn't think about that.

    At first i was thinking it would be 52Cr8 * something.

    Is there any chance you could explain why it is 52^8 please?

    Thankyou .
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  4. #4
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    Quote Originally Posted by AshleyT View Post
    Eight cards are selected with replacement from a pack of 52 playing cards, with 12 pictures, 20 odd cards and 20 even cards. How many different sequences of 8 are available?
    Are you sure it said “with replacement”?
    If it did then the same card can be drawn several times, as many as eight.
    Thus the answer 52^8.

    Please check to see if it could be “without replacement”.
    If it does, also see if it does say “sequences” instead of “hands”.
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    Quote Originally Posted by Plato View Post
    Are you sure it said “with replacement”?
    If it did then the same card can be drawn several times, as many as eight.
    Thus the answer 52^8.

    Please check to see if it could be “without replacement”.
    If it does, also see if it does say “sequences” instead of “hands”.
    I see, thankyou .

    Yea it says 'with replacement' and 'sequences'.

    Thanks for your time .
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