Eight cards are selected with replacement from a pack of 52 playing cards, with 12 pictures, 20 odd cards and 20 even cards.
- How many different sequences of 8 are available?
Thanks x
Hello, AshleyT!
Could you supply the exact wording of the problem?
And the entire problem?
We don't need the breakdown of the types of cards.
. . So I suspect there are more parts to the question.
Eight cards are selected with replacement from a pack of 52 playing cards.
How many different sequences of 8 are available?
Since there are 52 different (identifiable) cards,
. . there are: .$\displaystyle 52^8 \:\approx\:5.346 \times 10^{13}$ possible sequences.
Hey, thanks very much for the reply .
There are second parts of the question but that was the first part, and the part i was stuck with. I'm going to attempt the other parts now.
Basically the chapter is based around factorials and holds no examples of using powers, so i didn't think about that.
At first i was thinking it would be 52Cr8 * something.
Is there any chance you could explain why it is 52^8 please?
Thankyou .
Are you sure it said “with replacement”?
If it did then the same card can be drawn several times, as many as eight.
Thus the answer $\displaystyle 52^8$.
Please check to see if it could be “without replacement”.
If it does, also see if it does say “sequences” instead of “hands”.