Need help with this problem in a hurry
If 2 cards are drawn from a deck of 52 cards and not replaced, what is the probability that both cards will be hearts?
If I remember correctly the is a reduced samplespace problem.
the prob of drawing the first heart is
$\displaystyle \frac{13}{52}=\frac{1}{4}$
To draw the next heart the is
$\displaystyle \frac{12}{51}=\frac{4}{17}$
This is because of the 51 cards left 11 are hearts.
The the probability is $\displaystyle \frac{1}{4} \cdot \frac{4}{17}=\frac{1}{17}$
I hope this helps
Hello, Beth!
Another approach . . .
There are: .$\displaystyle {52\choose2} = 1326$ possible outcomes.If 2 cards are drawn from a deck of 52 cards and not replaced,
what is the probability that both cards will be Hearts?
There are: .$\displaystyle {13\choose2} = 78$ ways to draw two Hearts.
Therefore: .$\displaystyle P(\text{2 Hearts}) \;=\;\frac{78}{1326} \;=\;\boxed{\frac{1}{17}}$