1. ## Probability

There are 20 players in the team, 6 from Canada, same number from Australia and the rest of the players from 4 other clubs.

Two payers were to be pickedout at random to undergo a doping test.
a) What was probability that the 1 player picked for a doping test came from Canada?
b) What was probability that both players picked for a doping test came from Canada?
I kow that one is easy.. probably you won't bother yourself solving it, but please!!

2. Hello,

Originally Posted by ttG
There are 20 players in the team, 6 from Canada, same number from Australia and the rest of the players from 4 other clubs.

Two payers were to be pickedout at random to undergo a doping test.
a) What was probability that the 1 player picked for a doping test came from Canada?
b) What was probability that both players picked for a doping test came from Canada?
I kow that one is easy.. probably you won't bother yourself solving it, but please!!
I would bother

There are 6 players coming from Canada. Hence the probability of picking one player from Canada is 6/20.

Now, both players... This means that you pick the first one from Canada, with a probability 6/20.
After picking this one, there remain 5 Canadian players among 19. So the probability is 5/19.

---> (6/20)*(5/19)

3. Hello, ttG!

There are 20 players in the team, 6 Canadians and 14 Others.
Two players were to be picked at random to undergo a doping test.
There are: . ${20\choose2} = 190$ possible outcomes.

a) What is probability that one player is Canadian?
We want one Canadian: . ${6\choose1}= 6$ ways
. . and one Other: . ${14\choose1} = 14$ ways.

Hence, there are: . $6\cdot14 \:=\:84$ ways to pick one Canadian and one Other.

Therefore: . $P(\text{1 Canadian, 1 Other}) \:\;=\;\:\frac{84}{190} \:\;=\;\:\frac{42}{95}$

b) What is the probability that both players are Canadian?
There are: . ${6\choose2} = 15$ ways to pick two Canadians.

Therefore: . $P(\text{2 Canadians}) \;=\;\frac{15}{190} \;=\;\frac{3}{38}$

4. Thaanks!!That was elementary..