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Math Help - Probability

  1. #1
    ttG
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    Probability

    There are 20 players in the team, 6 from Canada, same number from Australia and the rest of the players from 4 other clubs.

    Two payers were to be pickedout at random to undergo a doping test.
    a) What was probability that the 1 player picked for a doping test came from Canada?
    b) What was probability that both players picked for a doping test came from Canada?
    I kow that one is easy.. probably you won't bother yourself solving it, but please!!
    Last edited by ttG; May 6th 2008 at 10:25 AM.
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  2. #2
    Moo
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    Hello,

    Quote Originally Posted by ttG View Post
    There are 20 players in the team, 6 from Canada, same number from Australia and the rest of the players from 4 other clubs.

    Two payers were to be pickedout at random to undergo a doping test.
    a) What was probability that the 1 player picked for a doping test came from Canada?
    b) What was probability that both players picked for a doping test came from Canada?
    I kow that one is easy.. probably you won't bother yourself solving it, but please!!
    I would bother

    There are 6 players coming from Canada. Hence the probability of picking one player from Canada is 6/20.

    Now, both players... This means that you pick the first one from Canada, with a probability 6/20.
    After picking this one, there remain 5 Canadian players among 19. So the probability is 5/19.

    ---> (6/20)*(5/19)
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  3. #3
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    Hello, ttG!

    There are 20 players in the team, 6 Canadians and 14 Others.
    Two players were to be picked at random to undergo a doping test.
    There are: . {20\choose2} = 190 possible outcomes.


    a) What is probability that one player is Canadian?
    We want one Canadian: . {6\choose1}= 6 ways
    . . and one Other: . {14\choose1} = 14 ways.

    Hence, there are: . 6\cdot14 \:=\:84 ways to pick one Canadian and one Other.

    Therefore: . P(\text{1 Canadian, 1 Other}) \:\;=\;\:\frac{84}{190} \:\;=\;\:\frac{42}{95}




    b) What is the probability that both players are Canadian?
    There are: . {6\choose2} = 15 ways to pick two Canadians.

    Therefore: . P(\text{2 Canadians}) \;=\;\frac{15}{190} \;=\;\frac{3}{38}

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  4. #4
    ttG
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    Thaanks!!That was elementary..
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