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Math Help - possibilities

  1. #1
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    Apr 2008
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    possibilities

    I can't work out how many combinations of results 4 different teams may have. They can either win, lose or draw.
    1 team = 3 (W,L,D)
    2 teams = 9 (WW, WL, WD, LL, LW, LD, DD, DL, DW)
    3 teams = 21 (I think)
    how many for 4, and what is the maths behind it\/ Thanks
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  2. #2
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    Aug 2007
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    For 1 team there are 3 possibilities.

    When there are 2 teams for each of the 3 possibilities for the first team there are the 3 possibilities of the next team. Draw it as a tree maybe.
    It's 3 * 3 at that point.

    Each time the number of possibilities triples. So in general it's 3 to the power of the number of teams.
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