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Math Help - number of possibilities

  1. #1
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    Question number of possibilities

    how many 3 person committees can be formed in a club with 8 members?
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  2. #2
    Moo
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    Hello,

    This is a problem dealing with combinations

    {3 \choose 8}=\frac{8!}{3!(8-3)!}
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  3. #3
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    Question help

    Quote Originally Posted by Moo View Post
    Hello,

    This is a problem dealing with combinations

    {3 \choose 8}=\frac{8!}{3!(8-3)!}
    i know the answer is 56...how to get this answer...
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  4. #4
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    You're talking of \binom{8}{3}<br />
, Moo.
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  5. #5
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    Quote Originally Posted by BeBeMala View Post
    i know the answer is 56...how to get this answer...

    \frac{{8!}}<br />
{{3!\left( {8 - 3} \right)!}} = \frac{{8!}}<br />
{{3!5!}} = \frac{{8 \cdot 7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2}}<br />
{{3 \cdot 2 \cdot 5 \cdot 4 \cdot 3 \cdot 2}} = 8 \cdot 7 = 56
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  6. #6
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    Exclamation

    Quote Originally Posted by flyingsquirrel View Post
    You're talking of \binom{8}{3}<br />
, Moo.
    the formula to solve this is n!/ (k! (n-k)!),where n=8 and k=3.therefore,when we fill in the numbers we have: 8!/(3!) (8-3)!)
    this becomes
    40320/(6 *5) =40320/(6*120)=40320/720=56
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  7. #7
    Moo
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    Quote Originally Posted by flyingsquirrel View Post
    You're talking of \binom{8}{3}<br />
, Moo.
    I never know which one is above and which one is below
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