The question is:

In how many ways can 8 different CD's be distributed to 3 people so that each person receives at least 2 CD's?

My solution:However, the correct answer is 6720. What have I done wrong? Any help is very much appreciated. Thanks

(8C2 * 6C3 * 3C3) * 3! = 3360

(number of ways that two people get 3 CD's and one person gets 2 CD's)

(8C2 * 6C2 * 4C4) * 3! = 2520

(number of ways that two people get 2 CD's and one people gets four CD's)

3360+2520= 5880