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Math Help - probability

  1. #1
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    probability

    2 Cards are drawn from a standard deck of 52 cards.

    A) Probability(3 face cards w/replacement) =

    B) Probability(2 queens or 2 black cards w/o replacement) =
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  2. #2
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    so a standard deck has 4*3=12 face cards.

    for A we get:

    P(F=3) = \frac{12}{52} \times \frac{12}{52} \times  \frac{12}{52} = \frac{27}{2197}

    and for B, it a little different, due to the fact that there is no replacement. We would get:

    P(Q=2) = \frac{4}{52} \times \frac{3}{51} = \frac{1}{221}

    P(K=2) = \frac{4}{52} \times \frac{3}{51} = \frac{1}{221}

    since we are interested in getting either set,we have:

    P(Q \cup K) = \frac{1}{221} +\frac{1}{221} = \frac{2}{221}
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