2 Cards are drawn from a standard deck of 52 cards.
A) Probability(3 face cards w/replacement) =
B) Probability(2 queens or 2 black cards w/o replacement) =
so a standard deck has 4*3=12 face cards.
for A we get:
$\displaystyle P(F=3) = \frac{12}{52} \times \frac{12}{52} \times \frac{12}{52} = \frac{27}{2197}$
and for B, it a little different, due to the fact that there is no replacement. We would get:
$\displaystyle P(Q=2) = \frac{4}{52} \times \frac{3}{51} = \frac{1}{221}$
$\displaystyle P(K=2) = \frac{4}{52} \times \frac{3}{51} = \frac{1}{221} $
since we are interested in getting either set,we have:
$\displaystyle P(Q \cup K) = \frac{1}{221} +\frac{1}{221} = \frac{2}{221} $