Ive been studying for a test ive got tomorrow, and i keep getting stuck on questions that i should know by now.-_-. heres some of them.
Find the z value to the right of the mean so that:
a. 53.98% of the area under the distribution curve lies to the left of it.
b. 71.90% ' '
c. 96.78% ' '
Im using my TI-84 but i also have a normal distribution chart thing. I wasnt sure how to approach this kind of problem. I have a memory of doing them in class, but once im out of class its over.--_--
thanks for the help
ahh thats right. invnorm. thanks a bunch! In my scurry of mass studying, ive seemed to misplaced about three pages of my notes. if you dont mind me asking, what do i enter in the inverse normal command? is it the number given, which is 53.98% and the number left over from 100%? which would be 46.02%
so, invrnorm(.5398,.4602)
this gives me the answer of .5601
by the way, thanks for the help so far.