1. ## Combination problems

A company that employees 6 managers, 15 clerical workers and 23 warehouse personnel is relocating and wants to create a committee that has representatives from each group to oversee the process. How many different ways can they select 2 managers, 4 clerical workers and 7 warehouse personnel to serve on this committee.

2. We are choosing 2 from 6, 4 from 15, and 7 from 23. Therefore,

$C(6,2)\cdot{C(15,4)}\cdot{C(23,7)}$

3. Originally Posted by TLC918
A company that employees 6 managers, 15 clerical workers and 23 warehouse personnel is relocating and wants to create a committee that has representatives from each group to oversee the process. How many different ways can they select 2 managers, 4 clerical workers and 7 warehouse personnel to serve on this committee.
${6 \choose 2} {15 \choose 4} {23 \choose 7} = .....$

4. ## solve it

m =6
c.w =15
w.p =23
selected people = m =2,c.w =4,w.p =7
6c2 x15c4 x23c7 = 6!/4! 2! x15!/11! 4! x 23!/16! 7! =501958 =502 ways. 3 s.f

yours friend

clement okhale.
cokhale@yahoo.com
nigeria.