1. ## spearmans rank

i am using spearmans rank for my homework. ive put the numbers into the formula but can get the answer can somebody help please:

P = 1 – (6∑23830)/60(60-1) =

2. Originally Posted by rexruffage
i am using spearmans rank for my homework. ive put the numbers into the formula but can get the answer can somebody help please:

P = 1 – (6∑23830)/60(60-1) =
The formula to calculate the Spearman's rank correlation coefficient is:

$\rho = 1-\frac{6\cdot \sum d_i^2}{n(n^2-1)}$

If (and only if) 23830 is the sum of the squared differences then you must calculate:

$\rho = 1-\frac{6 \cdot 23830}{60(60^2-1)} \approx 0.33787$