Hi all, need some help here,
Simplify
2n+2
. .Pn
2n
. .Pn
thanks
Solve $\displaystyle \frac{(2n+2)(2n+1)}{(n+2)(n+1)} = \frac{7}{2} \Rightarrow 2(2n+2)(2n+1)=7(n+2)(n+1) .....$
Expand both sides and re-arrange into the form:
quadratic = 0.
Solve this equation in the usual way, noting the restriction $\displaystyle n \geq 0$.
For checking purposes: n = 10.