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Math Help - Homework Help Please :D

  1. #1
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    Exclamation Homework Help Please :D

    Sita puts 5 balls in Box A and 4 Balls in Box B.
    The balls are numbered.


    Box A-balls numbered 1-5
    Box B-balls numbered 1-4

    What is the probability that both balls have odd numbers?




    I have done some working out and i think the answer may be 3/10
    Can anyone please confirm this for me and tell me how they got to that answer.

    Thankyou.
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  2. #2
    Behold, the power of SARDINES!
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    Quote Originally Posted by solid icy View Post
    Sita puts 5 balls in Box A and 4 Balls in Box B.
    The balls are numbered.
    Box A-balls numbered 1-5
    Box B-balls numbered 1-4

    What is the probability that both balls have odd numbers
    I have done some working out and i think the answer may be 3/10
    Can anyone please confirm this for me and tell me how they got to that answer.

    Thankyou.
    \frac{\binom{3}{1} \binom{2}{0}}{\binom{5}{1}} \cdot \frac{\binom{2}{1} \binom{2}{0}}{\binom{4}{1}}= \frac{3}{5} \cdot  \frac{2}{4}= \frac{3}{10}
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  3. #3
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    Hello, solid icy!

    You are correct!


    Sita puts 5 balls in Box A and 4 balls in Box B.
    . . Box A: balls are numbered 1 - 5
    . . Box B: balls are numbered 1 - 4
    A ball is drawn at random from each box.
    What is the probability that both balls have odd numbers?
    This problem is small enough to make a complete list.


    Here are the outcomes:

    . . \begin{array}{cccc}{\color{red}(1,1)} & (1,2) & {\color{red}(1,3)} & (1,4) \\ (2,1) & (2,2) & (2,3) & (2,4) \\ {\color{red}(3,1)} & (3,2) & {\color{red}(3,3)} & (3,4) \\ (4,1) & (4,2) & (4,3) & (4,4) \\ {\color{red}(5,1)} & (5,2) & {\color{red}(5,3)} & (5,4) \end{array}

    Of the twenty outcomes, six have two odd numbers.


    Therefore: . P(\text{both odd}) \;=\;\frac{6}{20} \;=\;\boxed{\frac{3}{10}}

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