Hello, looi76!

Your answer is correct, but there's an easier approach.A coin is tossed 10 times.

(a) How many different sequences of heads and tails are possible?

For each coin there are two possible states: Heads or Tails.

. . With ten coins, there are: . possible outcomes.

There are: . ways.(b) How many different sequences containing 6 Heads and 4 Tails are possible?

There are 210 ways to get 6 Heads and 4 Tails(c) What is the probability of getting 6 Heads and 4 Tails?

. . out of the 1024 possible outcomes.

Therefore: .