Q::it Is Asked To Show That The Standard Deviation For Normal Distribution Is Approximately 25% More Than The Mean Deviation I Have Absolutely No Idea As To Proceed Can I Have A Descriptive Solution
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Originally Posted by pawan6719 Q::it Is Asked To Show That The Standard Deviation For Normal Distribution Is Approximately 25% More Than The Mean Deviation I Have Absolutely No Idea As To Proceed Can I Have A Descriptive Solution You need to work with the standard normal distribution, and so show that: $\displaystyle \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} |x|e^{-x^2/2}~dx \approx 1.25$ RonL
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