In a dozen eggs, the mean number of broken ones is .6 SD=.5 eggs I buy 3 dozen I expect to get 1.8 broken eggs. Whats the SD? I dont understand this...can someone please explain? Id really appreciate it!
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Originally Posted by Morgan82 In a dozen eggs, the mean number of broken ones is .6 SD=.5 eggs I buy 3 dozen I expect to get 1.8 broken eggs. Whats the SD? I dont understand this...can someone please explain? Id really appreciate it! The standard deviation scales as the square root of the number of cases. There we have a SD of the number of broken eggs for 1 doz of 0.5, so the SD for 3 doz is (0.5)(sqrt(3))~=0.867 RonL
Last edited by CaptainBlack; Mar 13th 2008 at 01:14 PM. Reason: because what it said before was incoherent and wrong at the same time
Originally Posted by Morgan82 In a dozen eggs, the mean number of broken ones is .6 SD=.5 eggs I buy 3 dozen I expect to get 1.8 broken eggs. Whats the SD? I dont understand this...can someone please explain? Id really appreciate it! $\displaystyle \sigma_n = \frac{\sigma}{\sqrt{n}} \Rightarrow \frac{1}{2\sqrt{3}} = 0.2887$
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