Hello,
The probability of each face appearing once is 3/18 = 1/6 (equiprobability)
If you want this face appear 3 times, it's . Because the throws are independent, this probability equals to P(face)^3, that is to say (1/6)^3
Can anyone help me with the following probability question please:
18 fair dice are thrown and the uppermost faces are investigated. What is the probability of each face appearing 3 times?
(That is the outcome will be {1,1,1,2,2,2,3,3,3,4,4,4,5,5,5,6,6,6}.
Many thanks to anyone who is able to help