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Math Help - Impossible Prob question .. HELP...

  1. #1
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    Post Impossible Prob question .. HELP...

    6. Application Nine horses are entered in a horse race. If you “box” three
    horses (three are chosen and they can finish in any of the first 3 positions in
    the race), determine the probability that you will hold the winning ticket.

    answere is 1/14
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  2. #2
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    There are \binom {9}{3} = 84 ways to choose three horses from nine.
    There are (3!) = 6 ways for those three horses to finish in the top three places:
    \frac {6} {84} = \frac {1} {14} .

    That is hardly an impossible question.
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  3. #3
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    Quote Originally Posted by wikji View Post
    6. Application Nine horses are entered in a horse race. If you “box” three
    horses (three are chosen and they can finish in any of the first 3 positions in
    the race), determine the probability that you will hold the winning ticket.

    answere is 1/14
    123 124 125 126 127 128 129 134 135 136 137 138 139 145 146 147 148 149 156 157 158 159 167 168 169 178 179 189 234 235 236 237 238 239 245 246 247 248 249 256 257 258 259 267 268 269 278 279 289 345 346 3473 348 349 356 357 358 359 367 368 369 378 379 389 456 457 458 459 467 468 469 478 479 489 567 568 569 578 579 589 678 679 689 789
    i think theres more then 1/14 cause thats a lot of codes these are the codes if u choose 3 horses and they are not boxed yet.
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