4. In how many ways can a group of 10 people be chosen from 6 adults and
8 children if the group must contain at least 2 adults?
Hello,wikji
This is a strange question . . .
4. In how many ways can a group of 10 people be chosen from 6 adults
and 8 children if the group must contain at least 2 adults?
Since there are only 8 children, every group of 10 will contain at least two adults.
The number of ways is: .$\displaystyle {14\choose10} \:=\:1,001$