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Math Help - Data Help!!! Counting Techniques

  1. #1
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    Unhappy Data Help!!! Counting Techniques

    A class has 12 students. In how many different ways can the students be put into groups of 3?

    Answere is 369 600
    Last edited by wikji; March 3rd 2008 at 02:12 PM. Reason: Need this for a credit
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  2. #2
    Junior Member roy_zhang's Avatar
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    Since the order of students within each group does not matter, we use combination as:

    \binom{12}{3}\binom{9}{3}\binom{6}{3}\binom{3}{3}=  369600
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  3. #3
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    Quote Originally Posted by wikji View Post
    A class has 12 students. In how many different ways can the students be put into groups of 3?
    Answere is 369 600
    That is not the answer to the problem as it is stated.
    That is the answer to this question: “A class has 12 students. In how many different ways can the students be put into teams of 3; a red team, a green team, a blue team, a brown team?” Someone might prefer being on the red team rather than being on a blue team. These are known as ordered partitions.

    But that is not the question as stated.
    This is like dividing the class into ‘study-groups’ where only content matters. These are known as unordered partitions.
    The answer in this case is \frac{{\left( {12} \right)!}}{{\left( {3!} \right)^4 \left( {4!} \right)}}=15400
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