# Thread: Data Help!!! Counting Techniques

1. ## Data Help!!! Counting Techniques

A class has 12 students. In how many different ways can the students be put into groups of 3?

2. Since the order of students within each group does not matter, we use combination as:

$\binom{12}{3}\binom{9}{3}\binom{6}{3}\binom{3}{3}= 369600$

3. Originally Posted by wikji
A class has 12 students. In how many different ways can the students be put into groups of 3?
The answer in this case is $\frac{{\left( {12} \right)!}}{{\left( {3!} \right)^4 \left( {4!} \right)}}=15400$