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Math Help - probability

  1. #1
    Junior Member ihmth's Avatar
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    probability

    An urn contains 4 white balls and 10 blue balls and a second urn contains 14 white balls and 5 blue balls. 1 ball is drawn from the first urn and placed in the second urn. What is the probability that a ball now drawn in the second urn is white?
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  2. #2
    GAMMA Mathematics
    colby2152's Avatar
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    Quote Originally Posted by ihmth View Post
    An urn contains 4 white balls and 10 blue balls and a second urn contains 14 white balls and 5 blue balls. 1 ball is drawn from the first urn and placed in the second urn. What is the probability that a ball now drawn in the second urn is white?
    P(white) = P(ball from first urn was white)P(white ball in second urn after transfer of white ball) + P(ball from first urn was blue)P(white ball in second urn after transfer of blue ball)

    This takes in account all situations.

    P(W) = \frac{4}{14}*\frac{15}{20} + \frac{10}{14}*\frac{14}{20}
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