Results 1 to 3 of 3

Math Help - helpp plz

  1. #1
    Newbie
    Joined
    May 2006
    Posts
    19

    helpp plz

    I was wondering if someone could help me solve this probability problem below.

    Each week Bob and three friends fromw ork pool their money together and buy 12 lottery tickets that are randomly and equally divided up among the group.

    a) In lotto mania, the game played by Bob and his friends, 6 winning numbers are seletced by random sampling w/o replacement from a bin of balls numbered 1 through 30. A player wins if the 6 numbers on his/her ticket match at least 5 numbers from the six winning numbers (order is irrelevant). If you buy a single ticket, what is the probability that you will win something? ANS: 0.0002442
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Grand Panjandrum
    Joined
    Nov 2005
    From
    someplace
    Posts
    14,972
    Thanks
    4
    Quote Originally Posted by skhan
    I was wondering if someone could help me solve this probability problem below.

    Each week Bob and three friends fromw ork pool their money together and buy 12 lottery tickets that are randomly and equally divided up among the group.

    a) In lotto mania, the game played by Bob and his friends, 6 winning numbers are seletced by random sampling w/o replacement from a bin of balls numbered 1 through 30. A player wins if the 6 numbers on his/her ticket match at least 5 numbers from the six winning numbers (order is irrelevant). If you buy a single ticket, what is the probability that you will win something? ANS: 0.0002442
    There are 30 \choose 6 possible outcomes of the draw.

    Of these exactly 1 matches all six of your numbers.

    Also there are exactly 24 which match all but you smallest number (that
    is the miss-matched number can be any of the numbers other than the
    five matched or the unmatched number)

    The same goes for the cases where it is the next smallest that is mis-matched, and the next ..

    So there are 1+24+24+24+24+24+24=1+6\times 25 winning outcomes.
    Therefore the probability P of winning is the ratio of the number of
    winning outcomes to the number of all outcomes, so:

    <br />
P=\frac{1+6 \times 24}{{30 \choose 6}}=\frac{145}{593775}\approx0.0002442<br />

    RonL
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    May 2006
    Posts
    19
    Thanks Ron! This helps me to do the rest of the questions on my own
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. helpp
    Posted in the Geometry Forum
    Replies: 1
    Last Post: March 24th 2009, 12:45 PM
  2. Logarithm Helpp!!
    Posted in the Math Topics Forum
    Replies: 1
    Last Post: February 1st 2009, 09:04 PM
  3. Math Helpp
    Posted in the Calculus Forum
    Replies: 4
    Last Post: November 19th 2008, 06:24 PM
  4. helpp
    Posted in the Calculus Forum
    Replies: 1
    Last Post: September 23rd 2008, 01:58 PM
  5. Function helpp
    Posted in the Pre-Calculus Forum
    Replies: 3
    Last Post: December 7th 2006, 04:15 PM

Search Tags


/mathhelpforum @mathhelpforum