you throw 1 dice until you get K times the number '6' X = the number of your throws. what is P(X) ?
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The probability that N throws contains (K-1) '6's somewhere in the first (N-1) throws, with a '6' on the N-th throw is .
how can i prove that ∑ p(X)=1 ?
Originally Posted by amitbern how can i prove that ∑ p(X)=1 ? I'm not quite sure what you want to prove here. This sum has to be 1 since with probability 1 you will eventually reach K sixes. So the sum of the probabilities of the number of throws needed for this is 1. RonL
I know that it's supposed to be 1, but how can i prove it mathematically (Newton’s binomial )?
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