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Thread: Simple Probability Question

  1. #1
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    Simple Probability Question

    I've been trying to solve this for a few minutes and checking the rules in my book back and forth but I can't seem to understand why. P(A ∩ B) - P(A ∩ B^c) = P(A)?

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    here are my calculations in which I need to find P(A)

    below are the correction from the book which also says P(A ∩ B) - P(A ∩ B^c) = P(A). I thought it was only P(A ∩ B) + P(A ∩ B^c) = P(A)?

    Simple Probability Question-screen-shot-2019-06-17-7.14.47-am.png
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  2. #2
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    Re: Simple Probability Question

    Quote Originally Posted by steelmaste View Post
    I've been trying to solve this for a few minutes and checking the rules in my book back and forth but I can't seem to understand why. P(A ∩ B) - P(A ∩ B^c) = P(A)?
    You are correct. I would say that is a typo in your textbook.
    It is $\mathcal{P}(A)=\mathcal{P}(A\cap B){\bf\large{+}}\mathcal{P}(A\cap B^c)$
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