1. ## Probability question

I have that:

P(n.mn <= x)≈1-exp(-x)

I would like to understand how:

P(mn <= x)=1-exp(-nx)

Thank you!

2. ## Re: Probability question

$P[n \cdot m_n \leq x) \approx 1-e^{-x}$

Assuming $n >0$

$P\left[m_n \leq \dfrac{x}{n}\right]\approx 1-e^{-x}$

$u = \dfrac{x}{n},~x = n u$

$P\left[m_n \leq u\right] \approx 1- e^{-n u}$

$u$ is a dummy variable so just replace it by $x$

$P[m_n \leq x] \approx 1 - e^{- n x}$