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Thread: Probability question

  1. #1
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    Probability question

    I have that:

    P(n.mn <= x)≈1-exp(-x)

    I would like to understand how:

    P(mn <= x)=1-exp(-nx)

    Thank you!
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  2. #2
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    Re: Probability question

    $P[n \cdot m_n \leq x) \approx 1-e^{-x}$

    Assuming $n >0$

    $P\left[m_n \leq \dfrac{x}{n}\right]\approx 1-e^{-x}$

    $u = \dfrac{x}{n},~x = n u$

    $P\left[m_n \leq u\right] \approx 1- e^{-n u}$

    $u$ is a dummy variable so just replace it by $x$

    $P[m_n \leq x] \approx 1 - e^{- n x}$
    Thanks from mathfn
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