I have a Poisson distribution question, which I am stuck on for part d), here is the problem ( preparing for exams, and this is a worksheet our professor gave us but no answers to it):

Number of physics problems that Mike tries for any given week follows a Poisson distribution with $μ=3.$

a) what is the probability of Mike trying exactly $2 $ problems in any given week?

b) If we are given that Mike tries at least 8 problems in two weeks, what is the probability that he tries more than 10 problems in these two week?

Every problem that mike tries is independent of one another, and has a constant probability of $0.2$ of getting the problem correct. (Mike's number of tries at the problems is independent of him answering a problem correctly).

c) Mike tries 12 problems. What is the probability that he gets at most 3 problems correct?

d) What is the probability that mike answers no questions correctly in any of the given two weeks?

I can do $a),b),c)$, but I cant seem to do $d)$. I would appreciate the help.

EDIT:

d) Someone did suggest the answer was:

$$(\sum_{i=0}^{\infty}P(i)(1-0.2))^2$$

Where $P(i)$ denotes the probability of attempting $i$ problems. But I do not understand the reasoning behind this result at all.