Results 1 to 4 of 4
Like Tree2Thanks
  • 1 Post By Plato
  • 1 Post By HallsofIvy

Thread: Ten Counters

  1. #1
    Super Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    995
    Thanks
    42

    Ten Counters

    There are 10 counters in a bag: 3 are red, 2 are blue and 5 are green.The contents of the bag are shaken before Maxine randomly chooses one counter from the bag.What is the probability that shedoesn't pick a red counter?

    Let A = probability that Maxine chooses a red counter.

    P(A) = 3/10

    The probability that Maxine does not pick a red counter is 1 - P(A).

    1 - P(A) = 1 - 3/10

    1 - P(A) = (10/10) - (3/10)

    1 - P(A) = 7/10

    Correct?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor

    Joined
    Aug 2006
    Posts
    22,331
    Thanks
    3223
    Awards
    1

    Re: Ten Counters

    Quote Originally Posted by harpazo View Post
    There are 10 counters in a bag: 3 are red, 2 are blue and 5 are green.The contents of the bag are shaken before Maxine randomly chooses one counter from the bag.What is the probability that shedoesn't pick a red counter?
    Let A = probability that Maxine chooses a red counter. P(A) = 3/10
    The probability that Maxine does not pick a red counter is 1 - P(A).
    1 - P(A) = 1 - 3/10
    1 - P(A) = (10/10) - (3/10)
    1 - P(A) = 7/10
    Correct?
    Yes correct.

    Another approach is: seven out of ten are not red.
    Thanks from harpazo
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Apr 2005
    Posts
    20,219
    Thanks
    3341

    Re: Ten Counters

    Another way to look at this is that there are 7 "not-red" counters out of 10.
    Thanks from harpazo
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Super Member harpazo's Avatar
    Joined
    Sep 2014
    From
    NYC
    Posts
    995
    Thanks
    42

    Re: Ten Counters

    Another one for my notes.
    Follow Math Help Forum on Facebook and Google+


/mathhelpforum @mathhelpforum