There are 10 counters in a bag: 3 are red, 2 are blue and 5 are green.The contents of the bag are shaken before Maxine randomly chooses one counter from the bag.What is the probability that shedoesn't pick a red counter?

Let A = probability that Maxine chooses a red counter.

P(A) = 3/10

The probability that Maxine does not pick a red counter is 1 - P(A).

1 - P(A) = 1 - 3/10

1 - P(A) = (10/10) - (3/10)

1 - P(A) = 7/10

Correct?