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Thread: distributed Geometrically

  1. #1
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    distributed Geometrically

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  2. #2
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    Re: distributed Geometrically

    You're going to have to start posting what you've tried on all these.
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  3. #3
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    Re: distributed Geometrically

    Hi, Sure, here is my intentar.
    when X1 = 1, n=1, Y1= -1
    X2 = 2, n=2 Y2=-0.707
    X3 = 3, n=3, Y3=0
    X4 = 4, n=4, Y4=1
    X5 =5, n=5, Y5=2.242
    Y=(-1,0,1,2)
    therefore: P(Y=-1)=1/4
    P(Y=0) =1/4
    P(Y=1)=1/4
    P(Y=2)=0
    P(-1≤Y≤ 2)= 3/4

    I can not sure if is right.
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