i suppose 2 and 8 are included here.

to be even, the last digit must be 2,4,6 or 8. so there are 4 choices for the last digit. for the next digit, we have 6 choices (because there are 6 digits left), for the next, there are 5 choices (because we cannot choose something we already chose). continuing like this, we have the answer to be:

4(6)(5)(4)(3) = 1440

clarification here: what must come last?b) How many of the above numbers contain a 4 and if the digit 2 is there, it must come last