In how many ways 5 boys and 4 girls can be arranged such that exactly 2 girls (any) are together.

Here's my thinking;

5! * (C(4,2) * C(6,1) + C(2,1) * C(5,1) + C(4,1))

The boys can be arranged in any way. Group any 2 of the girls and they can choose from 6 different spots in line. Girl number 3 has 5 different spots to choose from. Then finally girl 4 has 4 spots to choose from.

Is this correct?