Suppose P(C|D) =0.59, P(D) =0.44, and P (D|C) =0.38. What is P(C) rounded to two decimal places? A) 0.42 b) 0.57 c) 0.68 d) 0.34?
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Originally Posted by xanxan0710 Suppose P(C|D) =0.59, P(D) =0.44, and P (D|C) =0.38. What is P(C) rounded to two decimal places? A) 0.42 b) 0.57 c) 0.68 d) 0.34? $\begin{gathered} {\text{P(C|D) = 0}}{\text{.59}} \Rightarrow P(C \cap D) = (0.59)(0.44)\text{ Why ?} \hfill \\ P(D|C) = 0.38 \to P(C \cap D) = (0.38) \cdot P(C)\text{ Why ?} \hfill \\ \end{gathered}$ Set equal and SOLVE!