Can anyone transpose this equation to solve for i as a function of A, P, n ie, i = .....
A = P(((1 + i)^{n }- 1)/( (1 - I) + (1 + i)^{n}))
Please show each step!
Sorry for the typo! Added = sign after A
Can anyone transpose this equation to solve for i as a function of A, P, n ie, i = .....
A = P(((1 + i)^{n }- 1)/( (1 - I) + (1 + i)^{n}))
Please show each step!
Sorry for the typo! Added = sign after A
Now that you have the equal sign, your equation is
The first, obvious step is to divide both sides by P:
Now multiply both sides by that denominator, :
.
Now, rather than expand that "1+ i" to the nth power, I would let x= 1+ i. Then i= x- 1 so 1- i= 1- x+ 1= 2- x so that can be written as and then
.
That is an nth degree polynomial equation for x. Unfortunately, there is no general method for solving nth degree polynomial equations.