a group of 8 people is to be chosen from 8 men and 6 women. whats the probability that the group contains the same number of men and women?
i tried $\displaystyle (8/14)^4 *(6/14)^4 $
a group of 8 people is to be chosen from 8 men and 6 women. whats the probability that the group contains the same number of men and women?
i tried $\displaystyle (8/14)^4 *(6/14)^4 $
If you look in the back of the book it says the answer is:
$\dfrac{\dbinom{8}{4}\dbinom{6}{4}}{\dbinom{14}{8} }$