a group of 8 people is to be chosen from 8 men and 6 women. whats the probability that the group contains the same number of men and women? i tried
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$\dfrac{\dbinom{8}{4}\dbinom{6}{4}}{\dbinom{14}{8} } = \dfrac{50}{143}$
Originally Posted by markosheehan a group of 8 people is to be chosen from 8 men and 6 women. whats the probability that the group contains the same number of men and women? i tried If you look in the back of the book it says the answer is: $\dfrac{\dbinom{8}{4}\dbinom{6}{4}}{\dbinom{14}{8} }$ Now you must explain that answer.
i get it now. its 4 men and 4 women all over the total choices