# Thread: Poisson Distribution (flaw per square metre)

1. ## Poisson Distribution (flaw per square metre)

How can we solve this question?

2. ## Re: Poisson Distribution (flaw per square metre)

These are all pretty straightforward

a) use the Poisson distribution $P[k] = \dfrac{\lambda^k e^{-\lambda}}{k!},~k=0,1,\dots$

here $\lambda = 0.5~flaws/pane$

$P[\text{at least 1 flaw}] = 1 - P[\text{0 flaws}]$

b) let $X$ be the number of flaws, distributed as in (a)

$E[Profit] = 5 P[X=0] - 3 P[X>0]$

c) here $\lambda = 2~flaws/pane$

find $P[X=0]$