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Thread: Probability word problem: Pet ownership

  1. #1
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    Probability word problem: Pet ownership

    We have a group of 27 people:

    Pets Owners
    0 4
    1 9
    2 8
    3 6

    We choose 1 person from the group. What are the odds that the person owns 3 pets if we know that the person owns at least 1 pet?
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  2. #2
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    Re: Probability word problem: Pet ownership

    you have to show some work on these, we're not just going to do them for you.
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  3. #3
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    Re: Probability word problem: Pet ownership

    There are 23 people who own at least 1 pet (you see why that is?) and 6 people who own exactly 3 pets. So the odds of selecting an owner of 3 pets if you know the person has at least 1 pet is ??
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  4. #4
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    Re: Probability word problem: Pet ownership

    Quote Originally Posted by ChipB View Post
    There are 23 people who own at least 1 pet (you see why that is?) and 6 people who own exactly 3 pets. So the odds of selecting an owner of 3 pets if you know the person has at least 1 pet is ??
    6 / 23 = 0.26

    ???
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  5. #5
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    Re: Probability word problem: Pet ownership

    Why the "???"? What do you understand about probability? Do you understand the meaning of "odds"?
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