Hi Guys,

I have spent some time reading and trying to understand lottery math but can't seem to understand how to get the answers to my question.

In a basic lottery you have 49 numbers and you choose 7 (7/49) The odds are 49*48*47*46*45*44*43 / 7*6*5*4*3*2*1 = 85,900,584

Now how about if the lottery was fixed? As in you knew 100% the first number being picked? If the number was 1, 5, or 10, how would you solve that? Knowing the first number is say 5 or 10 greatly reduces odds as the numbers are ranked numerically meaning no other sets of the numbers can be lower than the first number. So a number 10 as the first of seven would mean all 6 other numbers drawn would be between 11-49.

I just want to understand how to adjust my formula if i know the first number for sure.

Thanks!